dpnp.nancumsum

dpnp.nancumsum(a, axis=None, dtype=None, out=None)[source]

Return the cumulative sum of array elements over a given axis treating Not a Numbers (NaNs) as zero. The cumulative sum does not change when NaNs are encountered and leading NaNs are replaced by zeros.

For full documentation refer to numpy.nancumsum.

Parameters:

a ({dpnp.ndarray, usm_ndarray}) -- Input array.
axis ({None, int}, optional) -- Axis along which the cumulative sum is computed. The default (None) is to compute the cumulative sum over the flattened array.
dtype ({None, dtype}, optional) -- Type of the returned array and of the accumulator in which the elements are summed. If dtype is not specified, it defaults to the dtype of a, unless a has an integer dtype with a precision less than that of the default platform integer. In that case, the default platform integer is used.
out ({None, dpnp.ndarray, usm_ndarray}, optional) -- Alternative output array in which to place the result. It must have the same shape and buffer length as the expected output but the type will be cast if necessary.

Returns:

out -- A new array holding the result is returned unless out is specified as dpnp.ndarray, in which case a reference to out is returned. The result has the same size as a, and the same shape as a if axis is not None or a is a 1-d array.

Return type:

dpnp.ndarray

See also

dpnp.cumsum: Cumulative sum across array propagating NaNs.
dpnp.isnan: Show which elements are NaN.

Examples

>>> import dpnp as np
>>> np.nancumsum(np.array(1))
array(1)
>>> np.nancumsum(np.array([1]))
array([1])
>>> np.nancumsum(np.array([1, np.nan]))
array([1., 1.])
>>> a = np.array([[1, 2], [3, np.nan]])
>>> np.nancumsum(a)
array([1., 3., 6., 6.])
>>> np.nancumsum(a, axis=0)
array([[1., 2.],
       [4., 2.]])
>>> np.nancumsum(a, axis=1)
array([[1., 3.],
       [3., 3.]])